in case of a failure don't show $? twice
authorWolfram Schneider <wosch@indexdata.dk>
Thu, 20 Nov 2014 12:26:10 +0000 (13:26 +0100)
committerWolfram Schneider <wosch@indexdata.dk>
Thu, 20 Nov 2014 12:26:10 +0000 (13:26 +0100)
test/bin/bomb.pl

index 94f5c8d..974a4bc 100755 (executable)
@@ -69,7 +69,7 @@ $SIG{INT} = "IGNORE";
 alarm($timeout);
 
 system(@system) == 0
-  or die "system('@system') failed: ?='$?', !='$!', ^E='$^E', ?='$?'";
+  or die "system('@system') failed: ?='$?', !='$!', ^E='$^E'";
 
 1;